Oracle 1z0-830 Dumps

In the provided code, a list abc is created containing the strings "a", "b", and "c". The first forEach operation attempts to convert each element to uppercase by assigning x = x.toUpperCase();. However, this assignment only changes the local variable x within the lambda expression and does not modify the elements in the original list abc. Strings in Java are immutable, meaning their values cannot be changed once created. Therefore, the original list remains unchanged.

The second forEach operation iterates over the original list and prints each element. Since the list was not modified, the output will be the concatenation of the original elements: abc.

To achieve the output ABC, you would need to collect the transformed elements into a new list, as shown below:

java

List abc = List.of("a", "b", "c");

List upperCaseAbc = abc.stream()

map(String::toUpperCase)

collect(Collectors.toList());

upperCaseAbc.forEach(System.out::print);

In this corrected version, the map operation creates a new stream with the uppercase versions of the original elements, which are then collected into a new list upperCaseAbc. The forEach operation then prints ABC.

In this code, three static methods from the Boolean class are used: logicalAnd, logicalOr, and logicalXor. Each method takes two boolean arguments and returns a boolean result based on the respective logical operation.

Evaluation of Each Statement:

Boolean.logicalAnd(1 == 1, 2 < 1)

Operands:

1 == 1 evaluates to true.

2 < 1 evaluates to false.

Operation:

Boolean.logicalAnd(true, false) performs a logical AND operation.

The result is false because both operands must be true for the AND operation to return true.

Output:

System.out.print(false); prints false.

Boolean.logicalOr(1 == 1, 2 < 1)

Operands:

1 == 1 evaluates to true.

2 < 1 evaluates to false.

Operation:

Boolean.logicalOr(true, false) performs a logical OR operation.

The result is true because at least one operand is true.

Output:

System.out.print(true); prints true.

Boolean.logicalXor(1 == 1, 2 < 1)

Operands:

1 == 1 evaluates to true.

2 < 1 evaluates to false.

Operation:

Boolean.logicalXor(true, false) performs a logical XOR (exclusive OR) operation.

The result is true because exactly one operand is true.

Output:

System.out.print(true); prints true.

Combined Output:

Combining the outputs from each statement, the final printed result is:

nginx

falsetruetrue

In this code, the Calculable interface defines a single abstract method calculate that takes an int parameter and returns a long. The main method contains three lambda expressions assigned to variables c1, c2, and c3 of type Calculable.

Line 1:Calculable c1 = i -> i + 1;

This lambda expression takes an integer i and returns the result of i + 1. Since the expression i + 1 results in an int, and Java allows implicit widening conversion from int to long, this line compiles successfully.

Line 2:Calculable c2 = i -> Long.valueOf(i);

Here, the lambda expression takes an integer i and returns the result of Long.valueOf(i). The Long.valueOf(int i) method returns a Long object. However, Java allows unboxing of the Long object to a long primitive type when necessary. Therefore, this line compiles successfully.

Line 3:Calculable c3 = i -> { throw new ArithmeticException(); };

This lambda expression takes an integer i and throws an ArithmeticException. Since the method calculate has a return type of long, and throwing an exception is a valid way to exit the method without returning a value, this line compiles successfully.

Since all three lines adhere to the method signature defined in the Calculable interface and there are no type mismatches or syntax errors, the program compiles successfully.

In Java, array initialization can be performed in several ways, but certain syntaxes are invalid and will cause compilation errors. Let's analyze each declaration:

var array1 = new String[]{ "foo", "bar", "buz" };

This is a valid declaration. The var keyword allows the compiler to infer the type from the initializer. Here, new String[]{ "foo", "bar", "buz" } creates an anonymous array of String with three elements. The compiler infers array1 as String[]. This syntax is correct and compiles successfully.

var array2[] = { "foo", "bar", "buz" };

This declaration is invalid. While var can be used for type inference, appending [] after var is not allowed. The correct syntax would be either String[] array2 = { "foo", "bar", "buz" }; or var array2 = new String[]{ "foo", "bar", "buz" };. Therefore, this line will cause a compilation error.

var array3 = new String[3] { "foo", "bar", "buz" };

This declaration is invalid. In Java, when specifying the size of the array (new String[3]), you cannot simultaneously provide an initializer. The correct approach is either to provide the size without an initializer (new String[3]) or to provide the initializer without specifying the size (new String[]{ "foo", "bar", "buz" }). Therefore, this line will cause a compilation error.

var array4 = { "foo", "bar", "buz" };

This declaration is invalid. The array initializer { "foo", "bar", "buz" } can only be used in an array declaration when the type is explicitly provided. Since var relies on type inference and there's no explicit type provided here, this will cause a compilation error. The correct syntax would be String[] array4 = { "foo", "bar", "buz" };.

String array5[] = new String[]{ "foo", "bar", "buz" };

This is a valid declaration. Here, String array5[] declares array5 as an array of String. The initializer new String[]{ "foo", "bar", "buz" } creates an array with three elements. This syntax is correct and compiles successfully.

Therefore, the declarations that compile successfully are array1 and array5.

References:

Java SE 21 & JDK 21 - Local Variable Type Inference

Java SE 21 & JDK 21 - Arrays

In this code, two lists l1 and l2 are created and initialized as follows:

l1 Initialization:

Created using List.of("a", "b"), which returns an immutable list containing the elements "a" and "b".

Wrapped with new ArrayList<>(...) to create a mutable ArrayList containing the same elements.

l2 Initialization:

Created using Collections.singletonList("c"), which returns an immutable list containing the single element "c".

Wrapped with new ArrayList<>(...) to create a mutable ArrayList containing the same element.

State of Lists Before Collections.copy:

l1: ["a", "b"]

l2: ["c"]

Collections.copy(l1, l2):

The Collections.copy method copies elements from the source list (l2) into the destination list (l1). The destination list must have at least as many elements as the source list; otherwise, an IndexOutOfBoundsException is thrown.

In this case, l1 has two elements, and l2 has one element, so the copy operation is valid. After copying, the first element of l1 is replaced with the first element of l2:

l1 after copy: ["c", "b"]

l2.set(0, "d"):

This line sets the first element of l2 to "d".

l2 after set: ["d"]

Final State of Lists:

l1: ["c", "b"]

l2: ["d"]

The System.out.println(l1); statement outputs the current state of l1, which is ["c", "b"]. Therefore, the correct answer is C: [c, b].

Understanding Constructors vs. Methods in Java

In Java, aconstructormustnot have a return type.

The followingis NOT a constructorbut aregular method:

java

void Versailles() { // This is NOT a constructor!

Correct way to define a constructor:

java

public Versailles() { // Constructor must not have a return type

Since there isno constructor explicitly defined,Java provides a default no-argument constructor, which does nothing.

Why Does Compilation Fail?

void Versailles() is interpreted as amethod,not a constructor.

This means the default constructor (which does nothing) is called.

Since the method Versailles() is never called, the object fields remain uninitialized.

If the constructor were correctly defined, the output would be:

nginx

Hall of Mirrors has 17 mirrors.

The gardens cover 800 hectares.

How to Fix It

java

public Versailles() { // Corrected constructor

this.mirrorsCount = 17;

this.gardensHectares = 800;

System.out.println("Hall of Mirrors has " + mirrorsCount + " mirrors.");

System.out.println("The gardens cover " + gardensHectares + " hectares.");

}

Thus, the correct answer is:Compilation fails at line n1.

References:

Java SE 21 - Constructors

Java SE 21 - Methods vs. Constructors

The jdeps tool is a Java class dependency analyzer that can be used to understand the static dependencies of applications and libraries. It provides several command-line options to customize its behavior.

Valid jdeps Options:

--generate-open-module: Generates a module declaration (module-info.java) with open directives for the given JAR files or classes.

--list-deps: Lists the immediate dependencies of the specified classes or JAR files.

--generate-module-info: Generates a module declaration (module-info.java) for the given JAR files or classes.

--print-module-deps: Prints the module dependencies of the specified modules or JAR files.

--list-reduced-deps: Lists the reduced dependencies, showing only the packages that are directly depended upon.

Invalid Option:

--check-deps: There is no --check-deps option in the jdeps tool.

Conclusion:

Option A (--check-deps) is not a valid option of the jdeps command.

1. Valid Use Cases of var

var is alocal variable type inferencefeature.

The compilerinfers the type from the assigned value.

Example of valid use:

java

var a = 10; // Type inferred as int

var str = "Hello"; // Type inferred as String

2. Analyzing the Given Statements

Statement

Valid/Invalid

Reason

var a = 1;

Valid

Type inferred as int.

var b = 2, c = 3.0;

❌Invalid

var doesnot allow multiple declarationsin one statement.

var d[] = new int[4];

❌Invalid

Array brackets []are not allowedwith var.

var e;

❌Invalid

varrequires an initializer(cannot be declared without assignment).

var f = { 6 };

❌Invalid

{ 6 } is anarray initializer, which must have an explicit type.

var h = (g = 7);

Valid

g is assigned 7, and h gets its value.

Thus, the correct answers are:B, C, D, E

References:

Java SE 21 - Local Variable Type Inference (var)

Java SE 21 - var Restrictions

In Java, FileOutputStream and ObjectOutputStream are used for writing data to files, but they have different purposes and methods. Let's analyze each statement:

fos.write("Today");

The FileOutputStream class is designed to write raw byte streams to files. The write method in FileOutputStream expects a parameter of type int or byte[]. Since "Today" is a String, passing it directly to fos.write("Today"); will cause a compilation error because there is no write method in FileOutputStream that accepts a String parameter.

fos.writeObject("Today");

The FileOutputStream class does not have a method named writeObject. The writeObject method is specific to ObjectOutputStream. Therefore, attempting to call fos.writeObject("Today"); will result in a compilation error.

oos.write("Today");

The ObjectOutputStream class is used to write objects to an output stream. However, it does not have a write method that accepts a String parameter. The available write methods in ObjectOutputStream are for writing primitive data types and objects. Therefore, oos.write("Today"); will cause a compilation error.

oos.writeObject("Today");

The ObjectOutputStream class provides the writeObject method, which is used to serialize objects and write them to the output stream. Since String implements the Serializable interface, "Today" can be serialized. Therefore, oos.writeObject("Today"); is valid and compiles successfully.

In summary, the only statement that compiles without errors is oos.writeObject("Today");.

References:

Java SE 21 & JDK 21 - ObjectOutputStream

Java SE 21 & JDK 21 - FileOutputStream

In this code, a Stream containing the elements "a" and "b" is processed using the collect method. The collect method is a terminal operation that performs a mutable reduction on the elements of the stream using a Collector. In this case, custom implementations for the supplier, accumulator, and combiner are provided.

Components of the collect Method:

Supplier:

() -> new StringBuilder("c")

This supplier creates a new StringBuilder initialized with the string "c".

Accumulator:

StringBuilder::append

This accumulator appends each element of the stream to the StringBuilder.

Combiner:

(a, b) -> b.append(a)

This combiner is used in parallel stream operations to merge two StringBuilder instances. It appends the contents of a to b.

Execution Flow:

Stream Elements:"a", "b"

Initial StringBuilder:"c"

Accumulation:

The first element "a" is appended to "c", resulting in "ca".

The second element "b" is appended to "ca", resulting in "cab".

Combiner:

In this sequential stream, the combiner is not utilized. The combiner is primarily used in parallel streams to merge partial results.

Final Result:

The StringBuilder contains "cab". Therefore, the output of the program is:

nginx

cab

In this program, we have two classes, A and B, both implementing the Serializable interface, and a Test class with the main method.

Program Flow:

Serialization:

An instance of class A is created and assigned to the variable a.

An ObjectOutputStream is created to write to the file "o.ser".

The object a is serialized and written to the file.

The ObjectOutputStream is closed.

Deserialization:

An ObjectInputStream is created to read from the file "o.ser".

The program attempts to read an object from the file and cast it to an instance of class B.

The ObjectInputStream is closed.

Analysis:

Serialization Process:

The object a is an instance of class A and is serialized into the file "o.ser".

Deserialization Process:

When deserializing, the program reads the object from the file and attempts to cast it to class B.

However, the object in the file is of type A, not B.

Since A and B are distinct classes with no inheritance relationship, casting an A instance to B is invalid.

Exception Details:

Attempting to cast an object of type A to type B results in a ClassCastException.

The exception message would be similar to:

pgsql

Exception in thread "main" java.lang.ClassCastException: class A cannot be cast to class B

Conclusion:

The program compiles successfully but throws a ClassCastException at runtime when it attempts to cast the deserialized object to class B.

In this code, two StringBuffer objects, us and uk, are created with the values "US" and "UK", respectively. A stream is then created from these objects using Stream.of(us, uk).

The collect method is used with Collectors.joining("-", "=", ""). The joining collector concatenates the elements of the stream into a single String with the following parameters:

Delimiter ("-"):Inserted between each element.

Prefix ("="):Inserted at the beginning of the result.

Suffix (""):Inserted at the end of the result.

Therefore, the elements "US" and "UK" are concatenated with "-" between them, resulting in "US-UK". The prefix "=" is added at the beginning, resulting in the final output =US-UK.

In this code, a text block is defined using the """ syntax introduced in Java 13. Text blocks allow for multiline string literals, preserving the format as written in the code.

Text Block Analysis:

The text block is defined as:

java

String textBlock = """

j \

a \t

contentReference[oaicite:0]{index=0}

1. Why does the compilation fail?

The interface Special contains bar as int bar = 1;.

In Java, all interface fields are implicitly public, static, and final.

This means that bar is a constant (final variable).

The method add() contains bar--, which attempts to modify bar.

Since bar is final, it cannot be modified, causing acompilation error.

2. Correcting the Code

To make the code compile, bar must not be final. One way to fix this:

java

class SpecialImpl implements Special {

int bar = 1;

}

Or modify the add() method:

java

int add() {

return --foo + bar; // No modification of bar

}

Thus, the correct answer is:Compilation fails.

References:

Java SE 21 - Interfaces

Java SE 21 - Final Variables

Analyzing the thrower() Method Execution

java

int i = 0;

return i / i;

i / i evaluates to 0 / 0, whichthrows ArithmeticException (/ by zero).

Since catch (NumberFormatException e) doesnot matchArithmeticException, it is skipped.

The finally block always executes, printing:

nginx

Beaujolais Nouveau,

The exceptionpropagates backto main().

Handling the Exception in main()

java

try {

thrower();

System.out.print("Dom Pérignon, ");

} catch (Exception e) {

System.out.print("Chablis, ");

} finally {

System.out.print("Saint-Émilion");

}

Since thrower() throws ArithmeticException, it is caught by catch (Exception e).

"Chablis, "is printed.

Thefinally block always executes, printing "Saint-Émilion".

Final Output

nginx

Beaujolais Nouveau, Chablis, Saint-Émilion

Thus, the correct answer is:Beaujolais Nouveau, Chablis, Saint-Émilion

References:

Java SE 21 - Exception Handling

Java SE 21 - finally Block Execution

In this code, a HashMap is instantiated using the var keyword:

java

var ceo = new HashMap<>();

The diamond operator <> is used without explicit type arguments. While the diamond operatorallows the compiler to infer types in many cases, when using var, the compiler requires explicit type information to infer the variable's type.

Therefore, the code will not compile because the compiler cannot infer the type of the HashMap when both var and the diamond operator are used without explicit type parameters.

To fix this issue, provide explicit type parameters when creating the HashMap:

java

var ceo = new HashMap();

Alternatively, you can specify the variable type explicitly:

java

Map

contentReference[oaicite:0]{index=0}

Understanding java.util.function.Predicate<T>

The Predicate interface represents a function thattakes an input and returns a boolean(true or false).

It is often used for filtering operations in functional programming and streams.

Analyzing the Methods:

and(Predicate<? super T> other)→Default method

Combines two predicates usinglogical AND(&&).

java

Predicate startsWithA = s -> s.startsWith("A");

Predicate hasLength3 = s -> s.length() == 3;

Predicate combined = startsWithA.and(hasLength3);

❌isEqual(Object targetRef)→Static method

Not a default method, because it doesnot operate on an instance.

java

Predicate isEqualToHello = Predicate.isEqual("Hello");

negate()→Default method

Negates a predicate (! operator).

java

Predicate notEmpty = s -> !s.isEmpty();

Predicate isEmpty = notEmpty.negate();

❌not(Predicate<? super T> target)→Static method (introduced in Java 11)

Not a default method, since it is static.

or(Predicate<? super T> other)→Default method

Combines two predicates usinglogical OR(||).

❌test(T t)→Abstract method

Not a default method, because every predicatemust implement this method.

Thus, the correct answers are:and(Predicate<? super T> other), negate(), or(Predicate<? super T> other)

References:

Java SE 21 - Predicate Interface

Java SE 21 - Functional Interfaces

Understanding Sealed Classes in Java

Asealed classrestricts which other classes can extend it.

A sealed classmust explicitly declare its permitted subclassesusing the permits keyword.

Subclasses can be declared as:

sealed(restricts further extension).

non-sealed(removes the restriction, allowing unrestricted subclassing).

final(prevents further subclassing).

Analyzing the Given Code

Vehicle is declared as sealed with permits Car, Bike, meaning only Car and Bike can extend it.

Car is declared as non-sealed, which means itis no longer sealedand can have subclasses.

Bike is declared as final, meaningit cannot be subclassed.

Using isSealed() Method

vehicleClass.isSealed() →truebecause Vehicle is explicitly marked as sealed.

carClass.isSealed() →falsebecause Car is marked non-sealed.

bikeClass.isSealed() →falsebecause Bike is final, and a final class isnot considered sealed.

Final Output

csharp

Is Vehicle sealed? true; Is Car sealed? false; Is Bike sealed? false

Thus, the correct answer is:"Is Vehicle sealed? true; Is Car sealed? false; Is Bike sealed? false"

References:

Java SE 21 - Sealed Classes

Java SE 21 - isSealed() Method

Option A (Map<String, ArrayList<String>> authorsMap1 = new HashMap<>();)

❌Compilation Fails

frenchAuthors is declared as List,notArrayList.

The correct way to declare a Map that allows storing List is to use List as the generic type,notArrayList.

Fix:

java

Map> authorsMap1 = new HashMap<>();

authorsMap1.put("FR", frenchAuthors);

Reason:The type ArrayList is more specific than List, and this would cause atype mismatcherror.

Option B (Map<String, ? extends List<String>> authorsMap2 = new HashMap<String, ArrayList<String>>();)

❌Compilation Fails

? extends Listmakes the map read-onlyfor adding new elements.

The line authorsMap2.put("FR", frenchAuthors); causes acompilation errorbecause wildcard (? extends List) prevents modifying the map.

Fix:Remove the wildcard:

java

Map> authorsMap2 = new HashMap<>();

authorsMap2.put("FR", frenchAuthors);

Option C (var authorsMap3 = new HashMap<>();)

Compiles Successfully

The var keyword allows the compiler to infer the type.

However,the inferred type is HashMap<Object, Object>, which may cause issues when retrieving values.

Option D (Map<String, List<String>> authorsMap4 = new HashMap<String, ArrayList<String>>();)

Compiles Successfully

Valid declaration:HashMap can be assigned to Map.

Using new HashMap>() with Map> isalloweddue to polymorphism.

Correct syntax:

java

Map> authorsMap4 = new HashMap>();

authorsMap4.put("FR", frenchAuthors);

Option E (Map<String, List<String>> authorsMap5 = new HashMap<String, List<String>>();)

Compiles Successfully

HashMap> isa valid instantiation.

Correct usage:

java

Map> authorsMap5 = new HashMap<>();

authorsMap5.put("FR", frenchAuthors);

Thus, the correct answers are:C, D, E

References:

Java SE 21 - Generics and Type Inference

Java SE 21 - var Keyword

Understanding Variable Assignments

java

Integer frenchRevolution = 1789;

Object o1 = new String("1789");

Object o2 = frenchRevolution;

frenchRevolution = null;

frenchRevolution is an Integer with value1789.

o1 is aString with value "1789".

o2 storesa reference to frenchRevolution, which is an Integer (1789).

frenchRevolution = null;only nullifies the reference, but o2 still holds the Integer 1789.

Calling toString() on o2

java

Object o3 = o2.toString();

o2 refers to an Integer (1789).

Integer.toString() returns theString representation "1789".

o3 is assigned "1789" (String).

Evaluating o1.equals(o3)

java

System.out.println(o1.equals(o3));

o1.equals(o3) isequivalent to:

java

"1789".equals("1789")

Since both areequal strings, the output is:

arduino

true

Thus, the correct answer is:true

References:

Java SE 21 - Integer.toString()

Java SE 21 - String.equals()

Comprehensive and Detailed In-Depth Explanation:

Understanding Java Module Compilation (javac)

Java modules are compiled using the javac command with specific options to specify:

Where the source files are located (--module-source-path)

Where required dependencies (external modules) are located (-p / --module-path)

Where the compiled output should be placed (-d)

Breaking Down the Correct Compilation Command

css

CopyEdit

javac --module-source-path src -p lib/com.eiffel.membership.jar -d out -m com.eiffeltower.shop

--module-source-path src → Specifies the directory where module sources are located.

-p lib/com.eiffel.membership.jar → Specifies the module path (JAR dependency in lib).

-d out → Specifies the output directory for compiled .class files.

-m com.eiffeltower.shop → Specifies the module to compile (com.eiffeltower.shop).

In the verifyNotNull method, the following operations are performed:

Assertion to Enable Assertions:

java

boolean enabled = false;

assert enabled = true;

assert enabled;

The variable enabled is initially set to false.

The first assertion assert enabled = true; assigns true to enabled if assertions are enabled. If assertions are disabled, this assignment does not occur.

The second assertion assert enabled; checks if enabled is true. If assertions are enabled and the previous assignment occurred, this assertion passes. If assertions are disabled, this assertion is ignored.

Dereferencing the input Object:

java

System.out.println(input.toString());

This line attempts to call the toString() method on the input object. If input is null, this will throw a NullPointerException.

Assertion to Check input for null:

java

assert input != null;

This assertion checks that input is not null. If input is null and assertions are enabled, this assertion will fail, throwing an AssertionError. If assertions are disabled, this assertion is ignored.

Analysis:

If Assertions Are Enabled:

The enabled variable is set to true by the first assertion, and the second assertion passes.

If input is null, calling input.toString() will throw a NullPointerException before the final assertion is reached.

If input is not null, input.toString() executes without issue, and the final assertion assert input != null; passes.

If Assertions Are Disabled:

The enabled variable remains false, but the assertions are ignored, so this has no effect.

If input is null, calling input.toString() will throw a NullPointerException.

If input is not null, input.toString() executes without issue.

Conclusion:

A NullPointerException is thrown if input is null, regardless of whether assertions are enabled or disabled. Therefore, the correct answer is:

C. Only if assertions are disabled and the input argument is null

The var keyword and identifier rules:

The var keyword is used for local variable type inference introduced inJava 10.

However,Java does not allow _ (underscore) as an identifiersinceJava 9.

If we try to use _ as a variable name, the compiler will throw an error:

pgsql

error: as of release 9, '_' is a keyword, and may not be used as an identifier

The $ symbol as an identifier:

The $ characteris a valid identifierin Java.

However, since _ is not allowed, the codefails to compile before even reaching $.

Thus,the correct answer is "Compilation fails."

References:

Java SE 21 - var Local Variable Type Inference

Java SE 9 - Restrictions on _ Identifier

In this code, the class Main contains both an instance variable instanceVar and a static variable staticVar. The sequence of initialization and execution is as follows:

Static Variable Initialization:

staticVar is declared and initialized to 666.

Static Block Execution:

The static block executes, updating staticVar to 42.

Instance Variable Initialization:

When a new instance of Main is created, instanceVar is initialized to the current value of staticVar, which is 42.

main Method Execution:

The main method creates a new instance of Main and prints the values of instanceVar and staticVar.

Therefore, the output of the program is 42 42.

In this code, the try block throws an IOException. The catch block catches this exception and throws a new RuntimeException. Regardless of exceptions thrown in the try or catch blocks, the finally block is always executed. In this case, the finally block throws an ArithmeticException.

When an exception is thrown in a finally block, it overrides any previous exceptions that were thrown in the try or catch blocks. Therefore, the ArithmeticException thrown in the finally block is the exception that propagates out of the method. As a result, the program terminates with an ArithmeticException.